Q. 5 D5.0( 2 Votes )

# Prove the following :4(sin430° + cos4 60°) – 3(cos2 45° – sin290°) = 2

We know that,

Sin (90o) = 1

Now solving, L.H.S.

= 4[{(sin 30o)2}2 + {(cos 60o)2}2] – 3[(cos 45o)2 - (sin 90o)2]

Putting the values

=2 = R.H.S.

Hence Proved

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