Q. 55.0( 4 Votes )

# Draw the ΔPQR, where PQ = 6cm, ∠P = 110° and QR = 8cm and construct its centroid.

Answer :

Step-1:

Draw a line segment PQ with 6cm and take that as base. Take Q as Centre and draw an arc with 8cm radius, taking P as Centre draw ray of 110^{o} that should cut the previous arc. Name the intersection point as R and connect it to Q. Thus, triangle is formed.

STEP-2:

Draw perpendicular bisector for any two sides

We take QR side. Taking more than half of QR we draw arc on adjacent sides of line segment and from both the ends of the line segment (QR) and we connect the intersected points. Name the midpoint as T

STEP-3

In the same way we draw perpendicular bisector for PQ. Name the

midpoint as S

STEP-4:

Draw the medians PT, QS and name the meeting point is the centroid G

Thus, we have constructed centroid (G).

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