Q. 3 B4.2( 19 Votes )

# Factorise:

4x^{2} + 4x + 1

Answer :

using (x + y)^{2} = x^{2} + 2xy + y^{2}

= (2x)^{2} + 2 × 2x × 1 + 1^{2}

= (2x + 1)^{2}

= (2x + 1)(2x + 1)

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