Answer :

p + q = –5

p = –5–q


putting the value of q in other equation,


pq = –6


(–5–q)q = –6


–5q–q2 = –6


q2 + 5q–6 = 0


q2 + 6q–q–6 = 0


q(q + 6)–1(q + 6) = 0


(q–1)(q + 6) = 0


so, q = 1 & q = –6


as p = –5–q


thus, p = –5–1 & p = –5 + 6


p = –6 & p = 1


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Factorise:
</p
Karnataka Board - Mathematics Part I

Factorise:
</p
Karnataka Board - Mathematics Part I

Factorise:
</p
Karnataka Board - Mathematics Part I

In the following,Karnataka Board - Mathematics Part I

In the following,Karnataka Board - Mathematics Part I

In the following,Karnataka Board - Mathematics Part I

In the following,Karnataka Board - Mathematics Part I

Factorise:
</p
Karnataka Board - Mathematics Part I

Factorise:
</p
Karnataka Board - Mathematics Part I

Factorise:
</p
Karnataka Board - Mathematics Part I