Q. 1 D5.0( 1 Vote )

Construct trapezium PQRS with the following measurements. Find also its area.

is parallel to PQ = 6.5 cm,QR = 7 cm,PQR = 85°,PS = 9cm

Answer :

Given. PQRS is a trapezium.

PQ = 6.5 cm, QR = 7 cm, PS = 9 cm , PQR = 85°


Formula used. Area of trapezium = × height × sum of parallel sides


Area of trapezium = × height × (PQ + SR)


Steps of Construction


Step 1 : Draw a line PQ of 6.5cm


Step 2 : Make an angle of 85° from point Q and extend ray to QR’



Step 3 : Mark an arc of 7cm from Q on ray QR’ and name intersection point as R



Step 4 : Draw a ray RS’ parallel to PQ from point R



Step 5 : Make arc of 9cm on ray RS’ from point P and name intersection point as S



Step 6 : Join point S and P to form trapezium PQRS



Step 7 : Draw a perpendicular on PQ from point R and name the intersection point as E



Area of trapezium = × height × (PQ + SR)


= × RE × (PQ + SR)


= × 7cm × (6.5cm + 11.8cm)


64.05cm2


Conclusion. Hence; Trapezium PQRS is constructed and its area is 64.05cm2


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Squaring Using Geometry.Squaring Using Geometry.Squaring Using Geometry.43 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses