# In a right hypotenuse AC = 10 cm and ∠A = 60°, then find the length of the remaining sides.

Given: A = 60o and AC = 10cm

Now,

Now, we know that

BC = 53 cm

In right angled ∆ABC , we have

(AB)2 + (BC)2 =(AC)2 [by using Pythagoras theorem]

(AB)2 + (5√3)2 = (10)2

(AB)2 +(25×3) =100

(AB)2 +75 = 100

(AB)2 = 100 – 75

(AB)2 = 25

AB =25

AB = ±5

AB = 5cm [taking positive square root since, side cannot be negative]

Length of the side AB = 5cm and BC =53 cm

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