Q. 10 A4.8( 19 Votes )

Answer :

R1 → R1 + R2 + R3 (i.e. replace 1^{st} row by addition of 1^{st}, 2^{nd} and 3^{rd} row)

Taking 5x + 4 outside the determinant from 1^{st} row

C2 → C2 - C1 (i.e. replace 2^{nd} column by subtraction of 2^{nd} and 1^{st} column)

C3 → C3 - C1 (i.e. replace 3^{rd} column by subtraction of 3^{rd} and 1^{st} column)

Expanding the determinant along 1^{st} row

∴ LHS = (5x - 4) (4 - x)^{2} = RHS

∴

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