# Find the value of the following :(i) sin 30o + cos 60o(ii) sin2 45o+cos245o(iii) sin 30o + cos 60o – tan45o(iv) (v) tan 60o x cos30o

(i) sin 30o + cos 60o

We know that,

>  So,
sin(30
o) + cos(60o) =1

(ii) sin2 45o+cos245o

We know that,  So, sin2 45o+cos245o  =1

(iii) sin 30o + cos 60o – tan45o   So,
sin 30
o + cos 60o – tan 45o  =0

(iv) We know that

tan(60o) = √3

So,   =√4

= 2

(v) tan 60o × cos30o

tan(60o) = √3 So,

tan 60o × cos30o  Rate this question :

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