# Find the roots of

(i) X2 – 3x – 10

= x2 – 5x +2x – 10

= x(x – 5 ) + 2(x – 5 )

= (x – 5 )(x+2)

Roots of this equation are the values for which (x – 5 )(x+2) = 0

x - 5 = 0 or x + 2 = 0

i.e.,

x = 5 or x = -2

(ii) 2 x2 + x – 6

= 2x2 + 4x – 3x – 6

= 2x (x+2) – 3(x+2)

= (x+2)(2x – 3 )

Roots of this equation are the values for which (x+2)(2x – 3) = 0

x+ 2= 0 or 2x – 3 = 0

x = −2 or x = (iii)    Roots of this equation are the values for which = 0 = 0 or = 0 (iv)     Roots of this equation are the values for which (4x – 1 )2 = 0

Therefore,

(4x – 1 ) = 0 or (4x – 1) = 0

i.e., (v) 100x2 – 20x +1

= 100x2 – 10x – 10x +1

=10x(10x – 1) – 1 (10x – 1)

=(10x – 1)2

Roots of this equation are the values for which (10x – 1)2 = 0

Therefore,

(10x – 1) = 0 or (10x – 1) = 0

i.e., Rate this question :

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