# If then find the value of tan θ. We know that, Or  Let,

Base =BC = 4k

Hypotenuse =AC = 5k

Where, k ia any positive integer

So, by Pythagoras theorem, we can find the third side of a triangle

(AB)2 + (BC)2 = (AC)2

(AB)2 + (4k)2 = (5k)2

(AB)2 + 16k2 = 25k2

(AB)2 = 25 k2 –16 k2

(AB)2 = 9 k2

AB =9 k2

AB =±3k

But side AB can’t be negative. So, AB = 3k

Now, we have to find tan θ

We know that, Side opposite to angle θ = BC =4k

Side adjacent to angle θ = AB =3k

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