Q. 85.0( 1 Vote )

Draw quadrilateral ABCD with the following measurements. Find also its area.

AB = 5 cm, BD = 7 cm, BC = 4 cm, BAD = 100° and DBC = 60.

Answer :

Given. ABCD is a quadrilateral.

BAD = 100° and DBC = 60.


AB = 5 cm, BC = 4 cm, BD = 7 cm


Formula used. Area of triangle = × Base × Height


Steps for construction.


Step 1 : Draw a line AB of 5cm


Step 2 : Make an angle of 100° on point A and extend the ray to AD’



Step 3 : Make an arc on AD’ of 7cm from point B and mark the


intersection point as D



Step 4 : Make an angle of 60° on point B on BD and extend ray BC’



Step 5 : Mark an arc of 4cm from point B on BC’ and name the


intersection point as C.



Step 6 : Join C and D to form Quadrilateral ABCD


Step 6 : Draw perpendicular from A and C on BD and name the intersecting point as E and F respectively



Area of quadrilateral = Area of ΔABD + Area of ΔCBD


= × AE × BD + × CF × BD


= × BD × (AE + CF)


= × 7cm × (3.5cm + 2.9cm)


= 22.4cm2


Conclusion. Hence quadrilateral ABCD is constructed and its Area is


22.4cm2


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