Given. ABCD is a quadrilateral.
∠BAD = 100° and ∠DBC = 60.
AB = 5 cm, BC = 4 cm, BD = 7 cm
Formula used. Area of triangle = × Base × Height
Steps for construction.
Step 1 : Draw a line AB of 5cm
Step 2 : Make an angle of 100° on point A and extend the ray to AD’
Step 3 : Make an arc on AD’ of 7cm from point B and mark the
intersection point as D
Step 4 : Make an angle of 60° on point B on BD and extend ray BC’
Step 5 : Mark an arc of 4cm from point B on BC’ and name the
intersection point as C.
Step 6 : Join C and D to form Quadrilateral ABCD
Step 6 : Draw perpendicular from A and C on BD and name the intersecting point as E and F respectively
Area of quadrilateral = Area of ΔABD + Area of ΔCBD
= × AE × BD + × CF × BD
= × BD × (AE + CF)
= × 7cm × (3.5cm + 2.9cm)
Conclusion. Hence quadrilateral ABCD is constructed and its Area is
Rate this question :