Q. 7 B4.0( 14 Votes )

If calculate cos A and tan A.

Answer :

Given: Sin A

We know that,



Side opposite to angle θ = BC =3k

and Hypotenuse = AC =4k

where, k is any positive integer

So, by Pythagoras theorem, we can find the third side of a triangle

(AB)2 + (BC)2 = (AC)2

(AB)2 + (3k)2 = (4k)2

(AB)2 + 9k2 = 16k2

(AB)2 = 16 k2 – 9 k2

(AB)2 = 7 k2

AB =k7

So, AB = k√7

Now, we have to find the value of cos A and tan A

We know that,

Here, θ = A

The side adjacent to angle A = AB =k√7

Hypotenuse = AC =4k



We know that,

The side opposite to angle A = BC =3k

The side adjacent to angle A = AB =k√7


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