The angles of a t

Let the angles of the triangle be (a – d) °, a° and (a + d) °.

We know that the sum of the angles of a triangle is 180°.

⇒ a – d + a + a + d = 180°

⇒ 3a = 180°

∴ a = 60°

Given

⇒ 120 – 2d = 1

⇒ 2d = 119

∴ d = 59.5

Hence, angles are:

⇒ (a – d) ° = 60° – 59.5° = 0.5°

⇒ a° = 60°

⇒ (a + d) ° = 60° + 59.5° = 119.5°

∴ Angles of triangle in radians: