Q. 75.0( 1 Vote )

# <span lang="EN-US

AB = 5.5 cm, BC = 4.5cm, AC = 6.5 cm

CAD = 80° and ACD = 40°

Formula used. Area of triangle = × Base × Height

Steps for construction.

Step 1 : Draw a line AB of 5.5cm

Step 2 : Draw an arc of 6.5 cm from point A and 4.5cm from point B Step 3 : Mark the intersection point C and join AC and BC Step 4 : Make an angle of 80° on point A on AC and extend ray AD’ Step 5 : Make an angle of 40° on point C on AC and extend to

intersect at ray AD’ and mark the intersection point as D Step 6 : Draw perpendicular from B and D on AC and name the intersecting point as E and F respectively Area of quadrilateral = Area of ΔACB + Area of ΔACD

= × BE × AC + × DF × AC

= × AC × (BE + DF)

= × 6.5cm × (4.7cm + 3.8cm)

= 27.625cm2

Conclusion. Hence quadrilateral ABCD is constructed and its Area is

27.625cm2

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