Answer :

Given. ABCD is a quadrilateral.

AB = 7 cm, BC = 5 cm, CD = 4 cm , ACD = 45°, AC = 6 cm


Formula used. Area of triangle = × Base × Height


Steps for construction.


Step 1 : Draw a line AB of 7cm


Step 2 : Draw an arc of 6cm from point A and 5 cm from point B



Step 3 : Make the intersection point C and join AC and BC



Step 4 : Draw an angle of 45° on point C on AC



Step 5 : Make an arc of 4cm on ray CD’ and mark the intersection


point as D



Step 6 : Join A and D to form quadrilateral ABCD


Step 7 : Draw perpendicular from B and D on AC and name the intersecting point as E and F respectively



Area of quadrilateral = Area of ΔACB + Area of ΔACD


= × BE × AC + × DF × AC


= × AC × (BE + DF)


= × 6cm × (4.9cm + 2.9cm)


= 23.4cm2


Conclusion. Hence quadrilateral ABCD is constructed and its Area is


23.4cm2


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Squaring Using Geometry.Squaring Using Geometry.Squaring Using Geometry.43 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

<span lang="EN-USTamilnadu - Math Term-1

<span lang="EN-USTamilnadu - Math Term-1

<span lang="EN-USTamilnadu - Math Term-1

<span lang="EN-USTamilnadu - Math Term-1

<span lang="EN-USTamilnadu - Math Term-1

<span lang="EN-USTamilnadu - Math Term-1

<span lang="EN-USTamilnadu - Math Term-1

<span lang="EN-USTamilnadu - Math Term-1

<span lang="EN-USTamilnadu - Math Term-1

<span lang="EN-USTamilnadu - Math Term-1