Q. 5 C5.0( 1 Vote )

Find the values o

Answer :

Given: ∠AOD = y° ,∠DOC = 90°,∠COB = x° ,∠AOE = 3x and ∠BOE = 60°

Here AB is the straight line.

∴ ∠AOE and ∠BDC are linear pair.

⇒ ∠ADC + ∠BOE = 180°

⇒ 3x + 60° = 180°

⇒ 3x = 120°

⇒ x = 40°

Also, ∠AOD, ∠DOC and ∠BOC are linear pair.

⇒ ∠AOD + ∠DOC + ∠BOC = 180°

⇒ y + 90° + x° = 180°

⇒ y = 90° - 40°

⇒ y = 50°

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