Q. 534.3( 6 Votes )

If tan A + sec A = 3, find the value of sin A.

Answer :

tan A + sec A = 3

tanA = 3 secA


Squaring both the sides, we get


tan2 A =(3 – secA)2


tan2 A = 9 + sec2A – 6sec A


sec2 A – 1 = 9 + sec2A – 6sec A [ 1+ tan2 A = sec2 A]


–1 – 9 = –6secA


– 10 = –6sec A





Now, tan A + sec A = 3




sin A = 3cosA 1





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