Given. ABCD is a quadrilateral.
AB = 5.5 cm, BC = 6.5 cm , BD = 7 cm, AD = 5 cm , ∠BAC = 50°.
Formula used. Area of triangle = × Base × Height
Steps for construction.
Step 1 : Draw a line AB of 5.5cm
Step 2 : Make an angle of 50° on point A and extend the ray to AC’
Step 3 : Make an arc of 6.5cm from point B and mark the point of
intersection of arc and ray AC’ as point C.
Step 4 : Draw an arc of 7cm from point B and 5cm from point A
Step 5 : Mark the intersection point D and join AD and BD
Step 6 : Join C and D to form quadrilateral ABCD
Step 6 : Draw perpendicular from B and D on AC and name the intersecting point as E and F respectively
Area of quadrilateral = Area of ΔACB + Area of ΔACD
= × BE × AC + × DF × AC
= × AC × (BE + DF)
= × 8.5cm × (2.8cm + 4.2cm)
Conclusion. Hence quadrilateral ABCD is constructed and its Area is
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