Answer :

Given. ABCD is a quadrilateral.

AB = 5.5 cm, BC = 6.5 cm , BD = 7 cm, AD = 5 cm , BAC = 50°.


Formula used. Area of triangle = × Base × Height


Steps for construction.


Step 1 : Draw a line AB of 5.5cm


Step 2 : Make an angle of 50° on point A and extend the ray to AC’



Step 3 : Make an arc of 6.5cm from point B and mark the point of


intersection of arc and ray AC’ as point C.



Step 4 : Draw an arc of 7cm from point B and 5cm from point A



Step 5 : Mark the intersection point D and join AD and BD



Step 6 : Join C and D to form quadrilateral ABCD



Step 6 : Draw perpendicular from B and D on AC and name the intersecting point as E and F respectively


Area of quadrilateral = Area of ΔACB + Area of ΔACD


= × BE × AC + × DF × AC


= × AC × (BE + DF)


= × 8.5cm × (2.8cm + 4.2cm)


= 29.75cm2


Conclusion. Hence quadrilateral ABCD is constructed and its Area is


29.75cm2


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