Q. 4 A3.5( 2 Votes )

# Solve the followi

27 and 48 are divisible by 3 take factor 3 common

3 × (9x2 – 16) = 0

9x2 – 16 = 0

(3x)2 – 42 = 0

Using the identity (a + b)(a – b) = a2 – b2

Where a = 3x and b = 4

(3x + 4)(3x – 4) = 0

3x + 4 = 0 or 3x – 4 = 0

3x = – 4 or 3x = 4

Therefore and

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