If 5 sin2 θ + cos2 θ = 2, find the value of sin θ.

Given: 5 sin2 θ + cos2 θ = 2

5 sin2 θ + (1– sin2 θ) = 2 [ sin2 θ + cos2 θ = 1]

5 sin2 θ + 1 – sin2 θ = 2

4 sin2 θ = 2 – 1

4 sin2 θ = 1

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