Q. 475.0( 8 Votes )

# In the given figure ABC is right angled at B and BD is perpendicular to AC. Find (i) cos θ, (ii) cot α.

Firstly, we find the value of AC

In right angled ∆ABC

(AB)2 + (BC)2 = (AC)2

(12)2 + (5)2 = (AC)2

144+25 =(AC)2

(AC)2 =169

AC =√169

AC =±13

AC =13 [taking positive square root since, side cannot be negative]

(i)

(ii)

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