Answer :

Given:

Now, squaring both the sides, we get








p2 = q2 tan2θ …(1)


Now, solving LHS


Putting the value of p2 in the above equation, we get




[ 1+ tan2 θ = sec2 θ]




(from Eq. (1))



[(a + b) (a – b) = (a2 – b2)]



Now, we solve the RHS





[ 1+ tan2 θ = sec2 θ]




LHS = RHS


Hence Proved


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