Q. 45.0( 4 Votes )

Write the cubes of 5 natural numbers which are multiples of 3 and verify the followings:

“The cube of a natural number which is a multiple of 3 is a multiple of 27’

Answer :

First 5 natural numbers which are multiple of 3 are = 3 , 6 , 9 , 12 , 15


Now, cube of them are,


= 33 = 3 × 3 × 3 = 27


= 63 = 6 × 6 × 6 = 216


= 93 = 9 × 9 × 9 = 729


= 123 = 12 × 12 × 12 = 1728


= 153 = 15 × 15 × 15 = 3375


We find that all the cubes are divisible by 27,


Therefore, “The cube of a natural number which is a multiple of 3 is a multiple of 27’


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