Q. 45.0( 4 Votes )

# Write the cubes of 5 natural numbers which are multiples of 3 and verify the followings:

“The cube of a natural number which is a multiple of 3 is a multiple of 27’

Answer :

First 5 natural numbers which are multiple of 3 are = 3 , 6 , 9 , 12 , 15

Now, cube of them are,

= 3^{3} = 3 × 3 × 3 = 27

= 6^{3} = 6 × 6 × 6 = 216

= 9^{3} = 9 × 9 × 9 = 729

= 12^{3} = 12 × 12 × 12 = 1728

= 15^{3} = 15 × 15 × 15 = 3375

We find that all the cubes are divisible by 27,

Therefore, “The cube of a natural number which is a multiple of 3 is a multiple of 27’

Rate this question :

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