Given. ABCD is a quadrilateral.
AB = 6 cm, BC = 7 cm,AD = 6 cm, CD = 5 cm , ∠BAC = 45°
Formula used. Area of triangle = × Base × Height
Steps for construction.
Step 1 : Draw a line AB of 6cm
Step 2 : Draw an angle on point A of 45° and extend the ray to AC’
Step 3 : Make an arc of 7cm from point B and mark the point of
intersection of arc and ray AC’ as point C.
Step 4 : Draw an arc of 5cm from point C and 6cm from point A
Step 5 : Mark the intersection point D and join AD and DC
Step 6 : Draw perpendicular from B and D on AC and name the intersecting point as E and F respectively
Area of quadrilateral = Area of ΔACB + Area of ΔACD
= × BE × AC + × DF × AC
= × AC × (BE + DF)
= × 9.8 × (2.5cm + 4.2cm)
Conclusion. Hence quadrilateral ABCD is constructed and its Area is
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