Answer :

Given. ABCD is a quadrilateral.

AB = 6 cm, BC = 7 cm,AD = 6 cm, CD = 5 cm , BAC = 45°


Formula used. Area of triangle = × Base × Height


Steps for construction.


Step 1 : Draw a line AB of 6cm


Step 2 : Draw an angle on point A of 45° and extend the ray to AC’



Step 3 : Make an arc of 7cm from point B and mark the point of


intersection of arc and ray AC’ as point C.



Step 4 : Draw an arc of 5cm from point C and 6cm from point A



Step 5 : Mark the intersection point D and join AD and DC



Step 6 : Draw perpendicular from B and D on AC and name the intersecting point as E and F respectively



Area of quadrilateral = Area of ΔACB + Area of ΔACD


= × BE × AC + × DF × AC


= × AC × (BE + DF)


= × 9.8 × (2.5cm + 4.2cm)


= 32.83cm2


Conclusion. Hence quadrilateral ABCD is constructed and its Area is


32.83cm2


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