Q. 45.0( 1 Vote )

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AB = 6 cm, BC = 7 cm,AD = 6 cm, CD = 5 cm , BAC = 45°

Formula used. Area of triangle = × Base × Height

Steps for construction.

Step 1 : Draw a line AB of 6cm

Step 2 : Draw an angle on point A of 45° and extend the ray to AC’ Step 3 : Make an arc of 7cm from point B and mark the point of

intersection of arc and ray AC’ as point C. Step 4 : Draw an arc of 5cm from point C and 6cm from point A Step 5 : Mark the intersection point D and join AD and DC Step 6 : Draw perpendicular from B and D on AC and name the intersecting point as E and F respectively Area of quadrilateral = Area of ΔACB + Area of ΔACD

= × BE × AC + × DF × AC

= × AC × (BE + DF)

= × 9.8 × (2.5cm + 4.2cm)

= 32.83cm2

Conclusion. Hence quadrilateral ABCD is constructed and its Area is

32.83cm2

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