# If 4cot θ = 3, show that .

Given: cot θ  We know that, Or  Let,

Side adjacent to angle θ =AB = 3k

The side opposite to angle θ =BC = 4k

where k is any positive integer

Firstly we have to find the value of AC.

So, we can find the value of AC with the help of Pythagoras theorem

(AB)2 + (BC)2 = (AC)2

(3k)2 + (4k)2 = (AC)2

(AC)2 = 9k2 +16k2

(AC)2 = 25k2

AC =25k2

AC =±5k

But side AC can’t be negative. So, AC = 5k

Now, we will find the sin θ Side opposite to angle θ = BC = 4k

and Hypotenuse = AC = 5k

So, Now, we know that, Side adjacent to angle θ = AB =3k

Hypotenuse = AC =5k

So, Now, LHS   = 7 = RHS

Hence Proved

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Trigonometric Identities33 mins  Champ Quiz | Trigonometric Identities33 mins  NCERT | Trigonometric Identities52 mins  Quiz | Task on Trigonometric Ratios46 mins  Algebraic Identities48 mins  Quiz | Practice Important Questions on Trigonometrical Identities46 mins  Quiz on Trigonometric Ratios31 mins  T- Ratios of Specified Angles58 mins  Trick to learn all Trigonometric Formulae28 mins  Testing the T- Ratios of Specified Angles57 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 