# If verify that: . We know that, Or  Let,

Side adjacent to angle θ =AB = 1k

Side opposite to angle θ =AC = k√3

where, k is any positive integer

Firstly we have to find the value of BC.

So, we can find the value of AC with the help of Pythagoras theorem

(AB)2 + (AC)2 = (BC)2

(1k)2 + (√3k)2 = (BC)2

(BC)2 = 1 k2 +3 k2

(BC)2 = 4 k2

BC =2 k2

BC =±2k

But side BC can’t be negative. So, BC = 2k

Now, we will find the sin θ and cos θ Side opposite to angle θ = AC = k√3

and Hypotenuse = BC = 2k

So Now, we know that, Side adjacent to angle θ = AB =1k

Hypotenuse = BC =2k

So, Now, LHS     = RHS

Hence Proved

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Champ Quiz | Trigonometric Identities33 mins  Trigonometric Identities33 mins  NCERT | Trigonometric Identities52 mins  Quiz | Task on Trigonometric Ratios46 mins  Algebraic Identities48 mins  Quiz on Trigonometric Ratios31 mins  Quiz | Practice Important Questions on Trigonometrical Identities46 mins  T- Ratios of Specified Angles58 mins  Trick to learn all Trigonometric Formulae28 mins  Testing the T- Ratios of Specified Angles57 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 