Given. ABCD is a quadrilateral.
AB = 8 cm, BC = 6.8 cm,CD = 6 cm, AD = 6.4 cm , ∠B = 50°.
Formula used. Area of triangle = × Base × Height
Steps for construction.
Step 1 : Draw a line AB of 8cm
Step 2 : Draw an angle of 50° on point B and extend the line 6.8cm
And make the end point as C
Step 3 : Draw an arc of 6cm from point C and 6.4cm from point A
Step 4 : Mark the intersection point D and join AD and DC
Step 5 : Join A and C to divide quadrilateral in two triangles
Step 6 : Draw perpendicular from B and D on AC and name the intersecting point as E and F respectively
Area of quadrilateral = Area of ΔACB + Area of ΔACD
= × BE × AC + × DF × AC
= × AC × (BE + DF)
= × 6.4 × (6.6cm + 5.3cm)
Conclusion. Hence quadrilateral ABCD is constructed and its Area is
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