Answer :

Given. ABCD is a quadrilateral.

AB = 8 cm, BC = 6.8 cm,CD = 6 cm, AD = 6.4 cm , B = 50°.


Formula used. Area of triangle = × Base × Height


Steps for construction.


Step 1 : Draw a line AB of 8cm


Step 2 : Draw an angle of 50° on point B and extend the line 6.8cm


And make the end point as C



Step 3 : Draw an arc of 6cm from point C and 6.4cm from point A



Step 4 : Mark the intersection point D and join AD and DC



Step 5 : Join A and C to divide quadrilateral in two triangles



Step 6 : Draw perpendicular from B and D on AC and name the intersecting point as E and F respectively



Area of quadrilateral = Area of ΔACB + Area of ΔACD


= × BE × AC + × DF × AC


= × AC × (BE + DF)


= × 6.4 × (6.6cm + 5.3cm)


= 38.08cm2


Conclusion. Hence quadrilateral ABCD is constructed and its Area is


38.08cm2


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