Q. 2 B5.0( 1 Vote )

# Verify whether the given value of x is a solution of the quadratic equation or not:

x^{2} + x — 2 = 0, x = 2

Answer :

x = 2 will be solution of quadratic equation x^{2} + x — 2 = 0 if x = 2 satisfies the given equation

put x = 2 in L.H.S of x^{2} + x — 2 = 0

⇒ L.H.S = 2^{2} – 2 + 2

⇒ L.H.S = 4

⇒ L.H.S ≠ R.H.S

Thus x = 2 does not satisfies the equation x^{2} + x — 2 = 0 hence x = 2 is not a solution

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