Answer :

Given: 13 cosθ = 5



We know that,




Let AB =5k and BC = 13k


In right angled ∆ABC, we have


B2 + P2 = H2


(5k)2 + P2 = (13k)2


P2 + 25k2 = 169k2


P2 = 169k2 – 25k2


P2 = 144k2


P =144k2


P = ±12k


P = 12k [taking positive square root since, side cannot be negative]



Now,




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