Q. 24 C3.7( 4 Votes )

# If , find the value of 1+ cos2 θ.

We know that,

Or

Let,

Side opposite to angle θ =AB = 8k

Side adjacent to angle θ =BC = 15k

where, k is any positive integer

Firstly we have to find the value of AC.

So, we can find the value of AC with the help of Pythagoras theorem

(AB)2 + (BC)2 = (AC)2

(8k)2 + (15k)2 = (AC)2

(AC)2 = 64k2+225k2

(AC)2 = 289 k2

AC =289 k2

AC =±17k

But side AC can’t be negative. So, AC = 17k

Now, we will find the cos θ

We know that

Side adjacent to angle θ = BC = 15k

and Hypotenuse = AC = 17k

So,

Now, we have to find the value of 1+ cos2 θ

Putting the value of cos θ, we get

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