# If , then find the values of sin θ and cos θ.

Given:  We know that, Let,

AB = √(m2 – n2) and BC = n

In right angled ∆ABC, we have

(AB)2 + (BC)2 = (AC)2 [by using Pythagoras theorem]

(√(m2 – n2))2 + (n)2 = (AC )2

m2 – n2 + n2 = (AC )2

(AC)2 = (m2)

AC = m2

AC = ±m

AC = m [taking positive square root since, side cannot be negative]

Now, we have to find the value of cos θ and sin θ

We, know that  and  Rate this question :

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