Answer :

Given. ABCD is a quadrilateral.

AB = 7 cm, BC = 6.5 cm,CD = 6 cm and DA = 4.5 cm,AC = 8 cm


Formula used. Area of triangle = × Base × Height


Steps for construction.


Step 1 : Draw a line AB of 7cm


Step 2 : Draw an arc of 8cm from point A and 6.5cm from point B



Step 3 : Make the intersection point C and join AC and BC



Step 4 : Draw an arc of 6cm from point C and 4.5cm from point A



Step 5 : Mark the intersection point D and join AD and DC



Step 6 : Draw perpendicular from B and D on AC and name the intersecting point as E and F respectively



Area of quadrilateral = Area of ΔACB + Area of ΔACD


= × BE × AC + × DF × AC


= × AC × (BE + DF)


= × 8cm × (3.3cm + 5.4cm)


= 34.8cm2


Conclusion. Hence quadrilateral ABCD is constructed and its Area is


34.8cm2


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

<span lang="EN-USTamilnadu - Math Term-1

<span lang="EN-USTamilnadu - Math Term-1

<span lang="EN-USTamilnadu - Math Term-1

<span lang="EN-USTamilnadu - Math Term-1

<span lang="EN-USTamilnadu - Math Term-1

<span lang="EN-USTamilnadu - Math Term-1

<span lang="EN-USTamilnadu - Math Term-1

<span lang="EN-USTamilnadu - Math Term-1

<span lang="EN-USTamilnadu - Math Term-1

<span lang="EN-USTamilnadu - Math Term-1