Q. 1 E4.0( 2 Votes )

# Examine whether t

For L.H.S use formula (a + b)(a – b) = a2 – b2

4x2 – 1 = 4x2 – 20x + 3x – 15

– 1 = – 17x – 15

– 1 + 17x + 15 = 0

17x + 14 = 0

0x2 + 17x + 14 = 0

Comparing equation 0x2 + 17x + 14 = 0 with ax2 + bx + c = 0 we get

a = 0, b = 17 and c = 14

Here a, b, c R but a = 0

Therefore, the degree of polynomial 0x2 + 17x + 14 = 0 becomes 1

Hence (2x + 1)(2x — 1) = (4x + 3)(x — 5) is not a quadratic equation

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