Q. 105.0( 1 Vote )

# <span lang="EN-US

AB = 6 cm, BC = 6 cm, BAC = 50°, ACD = 30° and CAD = 100°

Formula used. Area of triangle = × Base × Height

Steps for construction.

Step 1 : Draw a line AB of 6cm

Step 2 : Draw an angle of 50° on point A and extend ray AC’

Step 3 : Make an arc of 6cm from point B and intersect it on AC’

Mark intersection point of arc and ray AC’ as point C

Step 4 : Draw an angle of 30° on point C on AC and extend

ray to CD’

Step 5 : Make an angle of 100° on point A on AC and extend ray to

intersect ray CD’ mark the intersection point as D

Step 6 : Join BD

Step 6 : Draw perpendicular from A and C on BD and name the intersecting point as E and F respectively

Area of quadrilateral = Area of ΔACB + Area of ΔACD

= × AE × BD + × CF × BD

= × BD × (AE + CF)

= × 10.5cm × (1.4cm + 5.5cm)

= 36.225cm2

Conclusion. Hence quadrilateral ABCD is constructed and its Area is

36.225cm2

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