Q. 105.0( 1 Vote )

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Answer :

Given. ABCD is a quadrilateral.

AB = 6 cm, BC = 6 cm, BAC = 50°, ACD = 30° and CAD = 100°


Formula used. Area of triangle = × Base × Height


Steps for construction.


Step 1 : Draw a line AB of 6cm


Step 2 : Draw an angle of 50° on point A and extend ray AC’



Step 3 : Make an arc of 6cm from point B and intersect it on AC’


Mark intersection point of arc and ray AC’ as point C



Step 4 : Draw an angle of 30° on point C on AC and extend


ray to CD’



Step 5 : Make an angle of 100° on point A on AC and extend ray to


intersect ray CD’ mark the intersection point as D



Step 6 : Join BD


Step 6 : Draw perpendicular from A and C on BD and name the intersecting point as E and F respectively



Area of quadrilateral = Area of ΔACB + Area of ΔACD


= × AE × BD + × CF × BD


= × BD × (AE + CF)


= × 10.5cm × (1.4cm + 5.5cm)


= 36.225cm2


Conclusion. Hence quadrilateral ABCD is constructed and its Area is


36.225cm2


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