# <span lang="EN-GB

Let us assume, is the tenth-place digit and is the unit

Place digit of a two – digit number

The two digit number = 10x + y and reversed number = 10y + x

According to the question

y = 2x(i)

Given,

10x + y + 27 = 10y + x

9y-9x = 27

y-x = 3

(divide by 9 on both the sides)

y = 3 + x(ii)

Substitute the value of y from (i) in(ii)

2x = 3 + x

2x-x = 3

x = 3

y = 2x = 2 × 3 = 6

Hence the two digit number = 10x + y = 10 × 3 + 6 = 36

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