Q. 85

The sum of three consecutive integers is 5 more than the smallest of the integers. Find the integers.

Answer :

Let one number be x. Then, the next two consecutive numbers will be x + 1 and x + 2. Sum of these three numbers = x + (x + 1) + (x + 2) = 3x + 3


According to the question, 3x + 3 = x + 5


3x – x = 5 – 3


2x = 2


[Dividing both sides by 2]


x = 1


Hence, the numbers are 1, 1 + 1, 1 + 2, i.e. 1, 2, 3.


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