Q. 7

# Using the p

Taking LHS,

Firstly, multiply and divide R1, R2, R3 by x, y, z respectively, we get

[rearrange the terms]

Taking xyz common from the first and second column, we get

Applying C3 C3 + C1, we get

Taking common (xy + yz + xz) common from C3, we get

If any two columns (or rows) of a determinant are identical (all corresponding elements are same), then the value of determinant is zero.

Here, C2 and C3 are identical.

Hence,

LHS = RHS

Hence Proved

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

Using properties Mathematics - Board Papers

Using properties Mathematics - Board Papers

Using properties Mathematics - Board Papers

Prove the followiMathematics - Board Papers