Answer :

Given equation is,

4t-3-(3t + 1) = 5t-4

4t-3-3t-1 = 5t-4

t-4 = 5t-4

t-5t = -4 + 4 (transposing 5t to LHS and – 4 to RHS)

-4t = 0

Hence value of t is 0.

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