Q. 55.0( 4 Votes )

Using the propert

Answer :


By applying C1 C1 + C2 + C3, we get




Taking (3x + 4) common from first column, we get



By applying R2 R2 – R1, we get




By applying R3 R3 – R1, we get




Now, expanding along first column, we get


= (3x + 4) [1×{(16) – 0}]


= (3x + 4)(16)


= 16(3x + 4)


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