Answer :

let one number be ‘x’


Then other number be (40-x)


Let us suppose (40 – x)>x


According to the question. When each number is increased by 8. Then,


(40-x) + 8 = 3 × (x + 8)


48-x = 3x + 24


-x-3x = 24-48


-4x = -24




So, one number is 6


and other number = (40-6)


= 34


Difference between two numbers =


= 28


But in the question given that two differs by 40


28≠40.


Hence, it is not true.


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