Answer :


Explanation:


Given


Performing the operation C1 C1 – C3



Taking (z – x) common from C1,




= (z – x) [1 [0 – (y – z) (z – y)] - (xyz) [0 - (y - z)] + (x – z) [(z – y) – 0]]


= (z – x) (z – y) (-y + z – xyz + x – z)


= (z – x) (z – y) (x – y – xyz)


= (z – x) (y – z) (y – x + xyz)


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