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Let Sudesh’s age be x and Seema’s age be y.

According to the question,

x = 2y ……(1)

If 6 years are subtracted from Seema’s age then Seema's age = y – 6

If 4 years are added to Sudesh’s age then Sudesh’s age = x + 4

Now Sudesh is four times Seema's age

x + 4 = 4 (y – 6)

x + 4 = 4y – 24

Put value of x from (1)

2y + 4 = 4y – 24

4y – 2y = 24 + 4

2y = 26

y = 26/2

y = 13

Put y = 13 in (1)

x = 2y

x = 2 × 13

x = 26

Sudesh’s age 3 years ago = 26 – 3 = 23 years

Seema’s age 3 years ago = 13 – 3 = 10 years

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