Q. 314.7( 3 Votes )

The maximum value

Answer :

Given


Performing operations C1 C2 – C3 and C2 C2 – C3



= 0 – 0 + 1 (sin θ. cos θ)


Multiply and divide by 2,


= 1/2 (2sin θ cos θ)


We know that 2 sin θ cos θ = sin 2θ


= 1/2 (sin 2θ)


Since the maximum value of sin 2θ is 1, θ = 45°.


Δ = 1/2 (sin 2(45°))


= 1/2 sin 90°


= 1/2 (1)


Δ = 1/2

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