Q. 35.0( 3 Votes )

The perimet

Answer :

Given perimeter of right-angled triangle is 60 cm.

hypotenuse = h = 26 cm


Let the other two sides be a & b.


So, a + b + h = 60


a + b = 60 – 26


a + b = 34 ...... (i)


By Pythagoras theorem,


a2 + b2 = h2


(As shown below:


a2 + b2 = 262


(a + b)2 – 2ab = 676


342 – 2ab = 676


2ab = 1156 – 676


2ab = 480


ab = 240


Using (a – b)2 = a2 + b2 – 2ab


(a – b)2 = 676 – 2x240


(a – b)2 = 676 – 480


(a – b)2 = 196


a – b = 14 ...... (ii)


adding (i) &(ii);


2a = 48


a = 24


b = 10


So, the other two sides are 24 cm & 10cm.


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