Q. 3

# Subhash is 3 years older than his brother Suresh. 6 years ago Subhash's age was four times the age of Suresh. Find their present ages.

Answer :

Let Subhash’s age be x and his brother Suresh’s age be y.

According to question

x = y + 3 ……(1)

6 years ago, age of Subhash = x – 6 and age of Suresh = y – 6

x – 6 = 4 (y – 6)

x – 6 = 4y – 24

x – 4y = – 24 + 6

x – 4y = – 18

From (1) put value of x as y + 3

y + 3 – 4y = – 18

– 4y + y = – 18 – 3

– 3y = – 21

y = 7

Put y = 7 in equation (1)

x = 7 + 3

x = 10

∴ Subhash’s age is 10 years and Suresh’s age is 7 years.

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