Answer :
We have,
Applying C1→ C1 + C2 + C3, we get
Taking (2cos X + sin X) common from the first column, we get
Applying R2→ R2 – R1, we get
Applying R3→ R3 – R1, we get
Expanding |A| along C1, we get
⇒ (2cos X + sin X) [(1){(sin X – cos X)(sin X – cos X)}]
⇒ (2cos X + sin X)(sin X – cos X)2 = 0
⇒ 2cos X = -sin X or (sin X – cos X)2 = 0
⇒ tan X = -2 or tan X = 1
but tan X = -2 is not possible as for
So, tan X = 1
Hence, only one real distinct root exist.
Hence, the correct option is (c)
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