Q. 27

2 years ago Salim was thrice as old as his daughter and 6 years later he will be 4 years older than twice her age. How old are they now?

Answer :

Let Salim's present age be x and her daughter's present age be y.

2 years ago


Salim's age = x – 2


Salim's daughter age = y – 2


Salim was thrice as old as his daughter


Salim's age = 3 (y – 2)


x – 2 = 3y – 6


x – 3y = – 4 ……(1)


6 years later


Salim's age = x + 6


Salim's daughter age = y + 6


Salim will be 4 years older than twice her daughter's age


Salim's age = 4 + 2 (y + 6)


x + 6 = 4 + 2y + 12


x – 2y = 10 ……(2)


Eliminate (1) and (2), by subtracting equation (1) from equation (2)


x – 2 y – (x – 3 y) = 10 – (- 4)


- 2 y + 3 y = 10 + 4


y = 14


Put y = 14 in (2)


x – 2 (14) = 6


x = 28 + 6


x = 34


Therefore, Salim's age is 38 years and her daughter's age is 14 years.


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