Q. 205.0( 1 Vote )

# A farmer counts nine heads and 24 legs of Chickens and cows. How many has each of these Chickens and cows?

Legs counted = 24

Number of legs of a chicken = 2

Number of legs of a cow = 4

Let a number of chickens be x and number of cows be y.

Legs of chicken = 2x

Legs of cow = 4y

Total legs = 2x + 4y

2x + 4y = 24 divided by 2

x + 2y = 12 ……(1)

Both the chicken and cows have 1 head

Total heads = x + y

x + y = 9 ……(2)

Eliminate (1) and (2), Subtracting eq(2) from eq(1)

x + 2 y – ( x + y) = 12 – 9

y = 3

Putting value of y in equation 2,

x + y = 9

x + 3 = 9

x = 6

Therefore, there are 6 chickens and 3 cows.

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