# <span lang="EN-GB

Let the 3 consecutive multiples of 7 be 7, (7x + 7),(7x + 14)where x is a natural number.

As per the question,

7 + (7x + 7) + (7x + 14) = 357

21x + 21 = 357

21(x + 1) = 357

(divide both sides by 21)

x + 1 = 17

x = 17-1(transpose 1 to RHS)

Hence the smallest multiple of 7 is ,i.e. 112.

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