GIVEN : In rhombus SOAP,
SA = 4.3 cm
OP = 5 cm (diagonals)
Step 1 : Draw a rough sketch of rhombus SOAP and mark th given measurements.
The diagonals of a rhombus bisect each other perpendicularly.
SA and OP are diagonals of the rhombus SOAP which bisect each other at ‘B ie. ∠ SBO = 90° and OB = BP = = = 2.5cm.
Step 2 : Draw SA = 4.3cm (one diagonal of the rhombus SOAP) and draw a perpendicular bisector XY of it and mark the point of intersection as ‘B’.
Step 3 : As the other diagonal OP is perpendicular to SA , OP is a part of XY. So, with center ‘B’ and radius 2.5 cm (OB = BP = 2.5cm) draw 2 arcs on either sides of SA to cut XY at O and P.
Step 4 : Join S,O ;O,A ; A,P ; S,P to complete the required rhombus SOAP.
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